document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385718>Question 385718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a recatngle is 8 meters more than its width. If the area is 65 square meters, what are the length and width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272837 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 13 and 5. On some of these problems you can easily \"guess and check\" by knowing that the only factors of 65 are (1, 65), (5, 13). On other problems you can solve by letting the width be w and the length 8+w. Then the area is w(8+w) = 65, which can be solved for w using the quadratic formula (or factoring). </SPAN>\n" );
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