document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385413>Question 385413</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Andrew factored the expression -30x^3-9x^2-3x as -5x(6x^2-2x-1). But when Melissa applied the distributive law and multiplied out -5x(6x^2-2x-1), she got ; thus, Andrew’s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272732 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272732\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -30x^3-9x^2-3x<BR>\n" );
document.write( "=-3x(10x^2+3x+1)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );