document.write( "Question 385414: Find the center of the circle defined by the equation: 4x^2+4y^2+24x-56y+168=0. \n" ); document.write( "

Algebra.Com's Answer #272726 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Standard Form of an Equation of a Circle is         
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document.write( "4x^2+4y^2+24x-56y+168 = 0 
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document.write( "4x^2+ 24x + 4y^2-56y+168 = 0 
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document.write( "x^2 +6x +y^2 - 14y + 42 = 0 Completing both squares
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document.write( " (x+3)^2 -9 + (y -7)^2 -49 + 42 = 0
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document.write( " (x+3)^2 (y -7)^2 -16 = 0
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document.write( " (x+3)^2 (y -7)^2 = 16 
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document.write( "Center is Pt(-3,7)
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