document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385427>Question 385427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one positive number is 5 larger than another number. the sum of their squares is 53. find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272721 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272721\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be a,b, the larger a=5+b<BR>\n" );
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document.write( "sum of square : a^2+b^2=53=25+10b+b^2+b^2 =><BR>\n" );
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document.write( "=2b^2+10b-28=2(b^2+5b-14) |Viete's formula : sum=5, prod=-14 => -2*7)<BR>\n" );
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document.write( "=2(b-2)(b+7)<BR>\n" );
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document.write( "=> >The 2 numbers are (7,2), ( (-2,-7) is not solution since it should be positive)<BR>\n" );
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