document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385357>Question 385357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the formula for calculating the surface area of a barrel shape: 48\" tall, 20\" small Ø and 24\" large Ø? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272664 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total surface area of frustum of a cone =(pi*(R+r))*sqrt((R-r)^2+(+h^2))<BR>\n" );
document.write( "...<BR>\n" );
document.write( "(pi*(12+10))*sqrt((12-10)^2+(48^2))<BR>\n" );
document.write( "...<BR>\n" );
document.write( "=3320.4 in^2<BR>\n" );
document.write( "= </SPAN>\n" );
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