document.write( "Question 385354: Good Morning...
\n" ); document.write( "This is kind of a new concept for me so I am trying to get some help with it. I have to solve the following by method of substitution:
\n" ); document.write( "{3x-2y=13
\n" ); document.write( "{x+y=1
\n" ); document.write( "These are all together with the same bracket. I know I am supposed to solve them individually, but I am not sure how to get started. Do I just start filling in numbers? \r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( "Denise
\n" ); document.write( "

Algebra.Com's Answer #272660 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
3x-2y=13
\n" ); document.write( "....
\n" ); document.write( "x+y=1
\n" ); document.write( "x=1-y
\n" ); document.write( "substitute value of x in first equation
\n" ); document.write( "3x-2y=13
\n" ); document.write( "3*(1-y)-2y=13
\n" ); document.write( "3-3y-2y=13
\n" ); document.write( "3-5y=13
\n" ); document.write( "add -3 to both sides
\n" ); document.write( "3-3-5y=13-3
\n" ); document.write( "-5y=10
\n" ); document.write( "divide by -5
\n" ); document.write( "y=10/-5
\n" ); document.write( "\"%28highlight%28y+=-2%29%29\"
\n" ); document.write( "..
\n" ); document.write( "x+y =1 from (1)
\n" ); document.write( "plug value of y =-2
\n" ); document.write( "x-2=1
\n" ); document.write( "\"%28highlight%28x=3%29%29\"
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca\r
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