document.write( "Question 385354: Good Morning...
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document.write( "This is kind of a new concept for me so I am trying to get some help with it. I have to solve the following by method of substitution:
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document.write( "{3x-2y=13
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document.write( "{x+y=1
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document.write( "These are all together with the same bracket. I know I am supposed to solve them individually, but I am not sure how to get started. Do I just start filling in numbers? \r
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document.write( "Thanks,
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document.write( "Denise \n" );
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Algebra.Com's Answer #272660 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 3x-2y=13 \n" ); document.write( ".... \n" ); document.write( "x+y=1 \n" ); document.write( "x=1-y \n" ); document.write( "substitute value of x in first equation \n" ); document.write( "3x-2y=13 \n" ); document.write( "3*(1-y)-2y=13 \n" ); document.write( "3-3y-2y=13 \n" ); document.write( "3-5y=13 \n" ); document.write( "add -3 to both sides \n" ); document.write( "3-3-5y=13-3 \n" ); document.write( "-5y=10 \n" ); document.write( "divide by -5 \n" ); document.write( "y=10/-5 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "x+y =1 from (1) \n" ); document.write( "plug value of y =-2 \n" ); document.write( "x-2=1 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |