document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42118>Question 42118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If y varies inversely as x and y=2 when x=6, find y when x=36. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27266 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We write the inverse relation as<BR>\n" );
document.write( "y = k/x<BR>\n" );
document.write( "2 = k/6<BR>\n" );
document.write( "we find k = 12<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "y = 12/x<BR>\n" );
document.write( "y = 12/36<BR>\n" );
document.write( "y = 1/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );