document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385337>Question 385337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line passing through the point (3,1) and parallel to the line which joins (3,-2) and (6,4). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272643 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line passing through the point (3,1) and parallel to the line which joins (3,-2) and (6,4).<BR>\n" );
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document.write( "slope of the given line = (4--2)/(6-3) = 2<BR>\n" );
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document.write( "Equation of line with slope = 2 passing thru (3,1).<BR>\n" );
document.write( "--<BR>\n" );
document.write( "Form: y = mx + b<BR>\n" );
document.write( "Substitute for y,x,m and solve for \"b\":<BR>\n" );
document.write( "1 = 2*3+b<BR>\n" );
document.write( "b = -5<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "y = 2x-5<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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