document.write( "Question 385297: the digits 4,5,6,7,8,9 are randomly arranged to form a three-digit number. (digits are not repeated) find the probability that the number is even and greater than 900 \n" ); document.write( "
Algebra.Com's Answer #272642 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "Total number of 3-digit numbers that can be formed = 6P3 = 120\r
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\n" ); document.write( "\n" ); document.write( "now we find no. of 3-digit numbers that is even and greater than 900 .......\r
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\n" ); document.write( "\n" ); document.write( "number should be in this form : 9XE\r
\n" ); document.write( "\n" ); document.write( " where E is an even number and X is any digit except 9 and digit on E.\r
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\n" ); document.write( "\n" ); document.write( " no. of ways to put an even digit at E i.e third place = 3 (4,6 or 8)\r
\n" ); document.write( "\n" ); document.write( "no. of ways to put any digit at X i.e second place= 4
\n" ); document.write( " (except 9 and which at E )\r
\n" ); document.write( "\n" ); document.write( "no. of ways to put 9 at first place = 1\r
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\n" ); document.write( "\n" ); document.write( "total no. = 1* 3 * 4 = 12
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\n" ); document.write( "\n" ); document.write( "thus, required probability = 12/120 = 1/10 \r
\n" ); document.write( "\n" ); document.write( " = 0.1\r
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