document.write( "Question 385309: The length of a rectangle is 2in. less than 7 times its width. the area of the rectangle is 57 sq. in. What are the dimentions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #272631 by mananth(16946)\"\" \"About 
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width = x
\n" ); document.write( "length = 7x-2
\n" ); document.write( "..
\n" ); document.write( "L*W= Area
\n" ); document.write( "...
\n" ); document.write( "x(7x-2)=57
\n" ); document.write( "7x^2-2x=57
\n" ); document.write( "7x^2-2x-57=0
\n" ); document.write( "7x^2-21x+19x-57=0
\n" ); document.write( "7x(x-3)+19(x-3)=0
\n" ); document.write( "(x-3)(7x+19)=0
\n" ); document.write( "x= 3 which is positive
\n" ); document.write( "Width = 3 in
\n" ); document.write( "length = 7x-2 = 21-2=19 in.
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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