document.write( "Question 385309: The length of a rectangle is 2in. less than 7 times its width. the area of the rectangle is 57 sq. in. What are the dimentions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #272630 by texttutoring(324)\"\" \"About 
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Let w = width
\n" ); document.write( "Let L = length\r
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\n" ); document.write( "\n" ); document.write( "Length is 2 less than 7 times the width:\r
\n" ); document.write( "\n" ); document.write( "L = 7w - 2\r
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\n" ); document.write( "\n" ); document.write( "Formula for area of a rectangle is A = w*L, and we know that A = 57\r
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\n" ); document.write( "\n" ); document.write( "Substitute the formula for L into the equation, and solve for w:\r
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\n" ); document.write( "\n" ); document.write( "A= w*L
\n" ); document.write( "57 = w(7w-2)
\n" ); document.write( "57 = 7w^2 - 2w
\n" ); document.write( "0 = 7w^2 - 2w -57\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic equation (or WolframAlpha.com) to solve.\r
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\n" ); document.write( "\n" ); document.write( "You should find that w=3\r
\n" ); document.write( "\n" ); document.write( "This means that L is:\r
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\n" ); document.write( "\n" ); document.write( "L=7w-2
\n" ); document.write( "L=7(3)-2
\n" ); document.write( "L=21-2
\n" ); document.write( "L=19\r
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\n" ); document.write( "\n" ); document.write( "So the dimensions are w=3, L=19.
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