document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385321>Question 385321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What polygon, if any, has angle measures that add up to 5400 degrees? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272618 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There's a formula to find the angle total of a polygon if you know n, the number of sides.\r<BR>\n" );
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document.write( "Angle Total = (n-2) * 180\r<BR>\n" );
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document.write( "For this question, you know the angle total is 5400, so solve for n:\r<BR>\n" );
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document.write( "5400 = (n-2) * 180<BR>\n" );
document.write( "5400 / 180 = n-2<BR>\n" );
document.write( "30 = n-2<BR>\n" );
document.write( "n = 32\r<BR>\n" );
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document.write( "So the polygon has 32 sides. It is called an Icosidodecagon, and you can view it here:\r<BR>\n" );
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document.write( "http://mathworld.wolfram.com/Icosidodecagon.html </SPAN>\n" );
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