document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=385236>Question 385236</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction on parallel tracks.  Train A is traveling at 100 miles per hour and train B is traveling at 110 miles per hour.  Train A passes a station at 4:20 A.M.  If train B passes the same station at 4:50 A.M., at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272610 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A and B are traveling in the same direction on parallel tracks.  Train A is traveling at 100 miles per hour and train B is traveling at 110 miles per hour.  Train A passes a station at 4:20 A.M.  If train B passes the same station at 4:50 A.M., at what time will train B catch up to train A?<BR>\n" );
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document.write( "Train A 4.20 A.M speed = 100 mph<BR>\n" );
document.write( "Train B 4.50 A.M speed = 110 mph<BR>\n" );
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document.write( "difference in time they reach station = 30 minutes = 1/2 hour.<BR>\n" );
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document.write( "catch up speed of train B will be 110-100 = 10 mph.<BR>\n" );
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document.write( "Train A has traveled 50 miles in 1/2 hour.<BR>\n" );
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document.write( "catch up time = 50/10 = 5 hours.<BR>\n" );
document.write( "Train B will catch up at 9;50 A.M<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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