document.write( "Question 385281: the area of a rectangle is 102 square inches. the length of the rectangle is 5 inches greater than twice the width. find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #272602 by richard1234(7193)\"\" \"About 
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It's possible to guess and check by taking the factors of 102 and seeing that (6, 17) works.\r
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\n" ); document.write( "\n" ); document.write( "Or, we can convert this into an elementary algebra problem by assuming the width is x and the length is 2x + 5. Then,\r
\n" ); document.write( "\n" ); document.write( "x(2x + 5) = 102\r
\n" ); document.write( "\n" ); document.write( "2x^2 + 5x - 102 = 0\r
\n" ); document.write( "\n" ); document.write( "(2x + 17)(x - 6) = 0\r
\n" ); document.write( "\n" ); document.write( "x = -17/2 or x = 6 --> x = 6 because we take the positive value.
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