document.write( "Question 385262: 12y^2+5y-3 \n" ); document.write( "
Algebra.Com's Answer #272577 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to factor this.\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"12y%5E2%2B5y-3\", we can see that the first coefficient is \"12\", the second coefficient is \"5\", and the last term is \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"12\" by the last term \"-3\" to get \"%2812%29%28-3%29=-36\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-36\" (the previous product) and add to the second coefficient \"5\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-36\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-36\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,9,12,18,36\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-9,-12,-18,-36\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-36\".\r
\n" ); document.write( "\n" ); document.write( "1*(-36) = -36
\n" ); document.write( "2*(-18) = -36
\n" ); document.write( "3*(-12) = -36
\n" ); document.write( "4*(-9) = -36
\n" ); document.write( "6*(-6) = -36
\n" ); document.write( "(-1)*(36) = -36
\n" ); document.write( "(-2)*(18) = -36
\n" ); document.write( "(-3)*(12) = -36
\n" ); document.write( "(-4)*(9) = -36
\n" ); document.write( "(-6)*(6) = -36\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"5\":\r
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First NumberSecond NumberSum
1-361+(-36)=-35
2-182+(-18)=-16
3-123+(-12)=-9
4-94+(-9)=-5
6-66+(-6)=0
-136-1+36=35
-218-2+18=16
-312-3+12=9
-49-4+9=5
-66-6+6=0
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-4\" and \"9\" add to \"5\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-4\" and \"9\" both multiply to \"-36\" and add to \"5\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"5y\" with \"-4y%2B9y\". Remember, \"-4\" and \"9\" add to \"5\". So this shows us that \"-4y%2B9y=5y\".\r
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\n" ); document.write( "\n" ); document.write( "\"12y%5E2%2Bhighlight%28-4y%2B9y%29-3\" Replace the second term \"5y\" with \"-4y%2B9y\".\r
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\n" ); document.write( "\n" ); document.write( "\"%2812y%5E2-4y%29%2B%289y-3%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"4y%283y-1%29%2B%289y-3%29\" Factor out the GCF \"4y\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"4y%283y-1%29%2B3%283y-1%29\" Factor out \"3\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%284y%2B3%29%283y-1%29\" Combine like terms. Or factor out the common term \"3y-1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"12y%5E2%2B5y-3\" factors to \"%284y%2B3%29%283y-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"12y%5E2%2B5y-3=%284y%2B3%29%283y-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%284y%2B3%29%283y-1%29\" to get \"12y%5E2%2B5y-3\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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