document.write( "Question 385173: Getting lost in completing the square for 2x^2+5x+11=0
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document.write( "I am able to get to 2x^2+5x=-11 then do I divide everything by 2? That would give me a really complicated fraction of x^2+5x/2=-11/2 then I am lost...\r
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document.write( "Melody \n" );
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Algebra.Com's Answer #272540 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! completing the square for \n" ); document.write( "2x^2+5x+11=0 \n" ); document.write( "--- \n" ); document.write( "2x^2 + 5x = -11 \n" ); document.write( "2(x^2 + (5/2)x + (5/4)^2 = -11 + 2*(5/4)^2 \n" ); document.write( "---- \n" ); document.write( "2(x+(5/4))^2 = (-176/16)+(50/16) \n" ); document.write( "2(x+(5/4))^2 = (-126/16) \n" ); document.write( "(x+(5/4))^2 = (-63/16) \n" ); document.write( "x+(5/4) = (3/4)sqrt(7)i or x+(5/4) = -(3/4)sqrt(7)i \n" ); document.write( "--- \n" ); document.write( "x = -(5/4)+(3/4)sqrt(7)i or x = -(5/4)-(3/4)sqrt(7)i \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |