document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384886>Question 384886</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi Please help. \r<BR>\n" );
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document.write( "Partial differentiate the following, the d's are the 'curly' d's but couldnt get them on here Find df/dx, df/dy, d^2f=dx^2 and d^2f/dy^2 for f(x, y) = e^(x+y).sin(x - y). \r<BR>\n" );
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document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272426 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272426\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find df/dx and df/dy, just assume that y and x are constants respectively (I'm also using d = differential). So,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=df%2Fdx+=+e%5E%28x%2By%29%2Asin%28x-y%29+%2B+e%5E%28x%2By%29%2Acos%28x-y%29++=++e%5E%28x%2By%29+%28sin+%28x-y%29+-+cos%28x-y%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > (by the Product Rule)\r<BR>\n" );
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document.write( "Do the same for df/dy. Then you can find the second derivatives by taking the derivative of df/dx, df/dy. </SPAN>\n" );
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