document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384807>Question 384807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane took three hours to drive to her friend's home on the weekend. Her average speed was 85km/hr for the first two hours. What was her average speed for the last hour of the trip if her average speed was 75km/hr for the whole trip? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272393 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt;  r=d/t and t=d/r<BR>\n" );
document.write( "also<BR>\n" );
document.write( "Average Speed =(Total Distance)/(Total Time)<BR>\n" );
document.write( "Total Distance in this problem is distance traveled for first 2 hours plus distance traveled in last hour<BR>\n" );
document.write( "Total Time =3 hours<BR>\n" );
document.write( "For the first two hours, distance traveled was 85*2=170 mi<BR>\n" );
document.write( "Let d=distance traveled in the last hour<BR>\n" );
document.write( "Soooo, our equation to solve is:<BR>\n" );
document.write( "75=(170+d)/3<BR>\n" );
document.write( "225=170+d<BR>\n" );
document.write( "d=55 miles----distance traveled in last hour<BR>\n" );
document.write( "Average Speed for last hour was 55/1=55 mph<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "75=225/3<BR>\n" );
document.write( "75=75\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );