document.write( "Question 384758: I am asking this question again because I am just not sure I got it!
\n" ); document.write( "line passing thru (3,0) and (-1,-2) slope:1/2
\n" ); document.write( "so what is the equation of the line in y=mx+b form \n" ); document.write( "

Algebra.Com's Answer #272382 by Earlsdon(6294) $\"\"$ $\"About$

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The equation of the line passing through the points: (3, 0) and (-1, -2) and having a slope of $\"1%2F2\"$ in slope-intercept form: $\"y+=+mx%2Bb\"$ where the slope $\"m+=+1%2F2\"$ .
\n" ); document.write( "Start with:
\n" ); document.write( " $\"y+=+%281%2F2%29x%2Bb\"$ since you were given the slope, m. To find the value of b, the y-intercept, substitute the x- and y-coordinates from either one of the two given points. Let's choose (3, 0)
\n" ); document.write( " $\"y+=+%281%2F2%29x%2Bb\"$ Substitute x = 3 and y = 0.
\n" ); document.write( " $\"0+=+%281%2F2%29%283%29%2Bb\"$ Simplify.
\n" ); document.write( " $\"0+=+%283%2F2%29+%2B+b\"$ Subtract $\"3%2F2\"$ from both sides.
\n" ); document.write( " $\"-%283%2F2%29+=+b\"$ Now substitute this into the equation above to get:
\n" ); document.write( " $\"y+=+%281%2F2%29x-3%2F2\"$ \n" ); document.write( "

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