document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384773>Question 384773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two boys on bicycles start from the same place and ride in opposite directions. One rides twice as fast as the other one. in 3 hours, they are 27 kilometers apart. what is the rate of speed for each boy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272375 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272375\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two boys on bicycles start from the same place and ride in opposite directions. One rides twice as fast as the other one. in 3 hours, they are 27 kilometers apart. what is the rate of speed for each boy?<BR>\n" );
document.write( "----<BR>\n" );
document.write( "1st rider data:<BR>\n" );
document.write( "rate = x kmh ; time = 3 hrs ; distance = 3x km<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2nd rider data:<BR>\n" );
document.write( "rate = 2x kmh ; time = 3 hrs ; distance = 3(2x) = 6x km<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "distance + distance = 27 km<BR>\n" );
document.write( "3x + 6x = 27<BR>\n" );
document.write( "9x = 27<BR>\n" );
document.write( "x = 3 km/h (1st rider's speed)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2x = 6 km/h (2nd rider's speed)<BR>\n" );
document.write( "===================================<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );