document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384770>Question 384770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> express in polar form, using the smallest non-negative value for the argument.<BR>\n" );
document.write( "-1/2 + radical 3/2 i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272371 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> express in polar form, using the smallest non-negative value for the argument.<BR>\n" );
document.write( "-1/2 + radical 3/2 i<BR>\n" );
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document.write( "r = sqrt[(1/2)^2 + (sqrt(3)/2)^2] = sqrt[1/4 + 3/4] = 1<BR>\n" );
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document.write( "theta = arctan[(sqrt(3)/2)/(1/2)] = arctan[sqrt(3)] = 60 degrees<BR>\n" );
document.write( "--<BR>\n" );
document.write( "But the point is in the 2nd Quadrant so theta = 120 degrees or (2pi/3)<BR>\n" );
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document.write( "Polar Form: 1(cos(2pi/3)+isin(2pi/3))<BR>\n" );
document.write( "============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );