document.write( "Question 384716: find x' for x=(t) defined implactitly by the given equation evaluate x' at the indicated point \r
\n" ); document.write( "\n" ); document.write( "1) x^3 - tx^2 - 4 = o;(-3,-2)
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Algebra.Com's Answer #272347 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"+x%5E3+-tx%5E2+-+4=+0+\"
\n" ); document.write( "\"3x%5E2%2Adx-%28t%282x%2Adx%29%2Bx%5E2%2Adt%29=0\"
\n" ); document.write( "\"3x%5E2%2Adx-2xt%2Adx-x%5E2%2Adt=0\"
\n" ); document.write( "\"%283x%5E2-2xt%29%2Adx=x%5E2%2Adt\"
\n" ); document.write( "\"dx%2Fdt=x%5E2%2F%283x%5E2-2xt%29\"
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\n" ); document.write( "If \"t=-3\" and \"x=-2\", then,
\n" ); document.write( "\"dx%2Fdt=4%2F%2812-12%29\"
\n" ); document.write( "\"dx%2Fdt\" is undefined.
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\n" ); document.write( "If \"t=-2\" and \"x=-3\", then,
\n" ); document.write( "\"dx%2Fdt=9%2F%2827-12%29\"
\n" ); document.write( "\"dx%2Fdt=9%2F15\"
\n" ); document.write( "\"dx%2Fdt=3%2F5\"
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