document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384689>Question 384689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Andrew factored expression 14x^3 - 21x^2 - 7x as 7x(14x^2 - 21x - 7) but when Melissa applied the distribution law and multiplied out 7x(14x - 21x - 7), she got 98x^3 - 147x^2 - 49x; thus, Andrew's solution does not appear to check. Why is that? Help Andrew understand better. Explain reasoning and correctly factor the original expression if possible. If expression is prime, state this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272324 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 14x^3 - 21x^2 - 7x <BR>\n" );
document.write( "=7x(2x^2-3x-1) </SPAN>\n" );
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