document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384687>Question 384687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please and thank you\r<BR>\n" );
document.write( "\n" );
document.write( "The polynomial 0.041h - 0.018A - 2.69 can be used to estimate the lung capacity, in liters, of a female with height h cm and age A years. Find the lung capacity of a 50-year-old woman who is 190 cm tall. Round to the nearest liter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272323 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.041h - 0.018A - 2.69<BR>\n" );
document.write( "A=50<BR>\n" );
document.write( "h=190<BR>\n" );
document.write( "plug the value of A & h<BR>\n" );
document.write( "(0.04*190)-(0.018*50)-2.69<BR>\n" );
document.write( "=4.01<BR>\n" );
document.write( "...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28highlight%284liters%29%29 ALIGN=MIDDLE  ALT=\"%28highlight%284liters%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );