document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384665>Question 384665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joshua and Geraldine can finish cleaning the house in 2 hours. If it takes Joshua working alone 3 hours longer than it takes Geraldine working alone, how many hours will each need to finish the work alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272314 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/g amount of the job geraldine can do in 1 hr<BR>\n" );
document.write( "1/(g+3) amount of the job josh can do in 1 hr<BR>\n" );
document.write( "1/g + 1/(g+3) = 1/2 working togeter to do 1/2 the job. <BR>\n" );
document.write( "2(g+3)+2g=g^2+3g multiply each side by 2g(g+3) LCM.<BR>\n" );
document.write( "2g+6+2g=g^2+3g<BR>\n" );
document.write( "g^2-g-6=0<BR>\n" );
document.write( "(g-3)(g+2)=0<BR>\n" );
document.write( "g=3 hrs to do the job alone<BR>\n" );
document.write( "Josh will 6 hrs to do the job alone<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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