document.write( "Question 384665: Joshua and Geraldine can finish cleaning the house in 2 hours. If it takes Joshua working alone 3 hours longer than it takes Geraldine working alone, how many hours will each need to finish the work alone? \n" ); document.write( "
Algebra.Com's Answer #272312 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Joshua and Geraldine can finish cleaning the house in 2 hours. If it takes Joshua working alone 3 hours longer than it takes Geraldine working alone, how many hours will each need to finish the work alone? \n" ); document.write( "... \n" ); document.write( "Geraldine = xhours \n" ); document.write( "Joshua x+3 hours \n" ); document.write( "they both can do \n" ); document.write( "... \n" ); document.write( " \n" ); document.write( "they will take \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "x^2-3x=2(2x+3) \n" ); document.write( "x^2-3x=4x+6 \n" ); document.write( "x^2-3x-4x-6=0 \n" ); document.write( "x^2-7x-6=0 \n" ); document.write( "discriminant = 73 \n" ); document.write( " \n" ); document.write( "x1=7.77 hours \n" ); document.write( "Geraldine \n" ); document.write( "Joshua \n" ); document.write( ".. \n" ); document.write( "x2 will be negative so ignore \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |