document.write( "Question 384677: Solve: -3 less than or equal to 2x-5/7 < 9 I have a test soon and can't figure this one out. Please help.
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Algebra.Com's Answer #272307 by edjones(8007)\"\" \"About 
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-3 <= 2x - 5/7 < 9
\n" ); document.write( "-21<=14x-5<63 Multiply each side by 7
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\n" ); document.write( "-21<=14x-5
\n" ); document.write( "-16<=14x
\n" ); document.write( "x>= -8/7
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\n" ); document.write( "14x-5<63
\n" ); document.write( "14x<68
\n" ); document.write( "x<34/7
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\n" ); document.write( "-8/7<=x<34/7
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