document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384666>Question 384666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the quadratic function f(x)=x^2 - 6x + 9 find a value of x such that <BR>\n" );
document.write( "f(x)= 25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272300 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have\r<BR>\n" );
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document.write( "25 = x^2 - 6x + 9\r<BR>\n" );
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document.write( "Factoring, we obtain\r<BR>\n" );
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document.write( "25 = (x - 3)^2\r<BR>\n" );
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document.write( "One such value of x is 8 (the other one is -2). </SPAN>\n" );
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