document.write( "Question 42088: Identify the vertex, axis of symmetry, and direction of opening for:\r
\n" ); document.write( "\n" ); document.write( "y=1/2(x-8)^2+2.\r
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Algebra.Com's Answer #27229 by venugopalramana(3286)\"\" \"About 
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Identify the vertex, axis of symmetry, and direction of opening for:
\n" ); document.write( "y=1/2(x-8)^2+2.
\n" ); document.write( "(X-8)^2=2(Y-2)
\n" ); document.write( "STD EQN.IS
\n" ); document.write( "(X-H)^2=4A(Y-K)
\n" ); document.write( "WHERE H,K IS VERTEX..SO..H=8...K=2...SO..(8,2) IS VERTEX
\n" ); document.write( "AXIS OF SYMMETRY IS X=H...OR....X=8
\n" ); document.write( "SINCE Y IS MINIMUM AT X=8,WE HAVE VERTEX AT THE BOTTOM AS A TROUGH.SO DIRECTION OF OPENING IS UPWARDS
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