document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384558>Question 384558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Parallelogram ABCD is inscribed in circle O. Find the measure of angle A. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272289 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By definition, if the parallelogram is inscribed in a circle, it is cyclic, and the measures of opposite angles add up to 180 (i.e. A + C = 180, B + D = 180). However, ABCD is a parallelogram, so A + B = 180, B + C = 180, etc. It follows that A = B, B = C, etc, so ABCD is a rectangle, and angle A = 90 degrees. </SPAN>\n" );
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