document.write( "Question 384638: the perimeter of a rectangle is 42 ft. The length of the rectangle is 3 ft less than twice the width.Find the length and the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #272287 by mananth(16946)\"\" \"About 
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width = w
\n" ); document.write( "length = 2w-3\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "2*(l+w)=perimeter
\n" ); document.write( "2*(w+2w-3)=42
\n" ); document.write( "2*(3w-3)=42
\n" ); document.write( "6w-6=42
\n" ); document.write( "+6 +6
\n" ); document.write( "6w=42+6
\n" ); document.write( "6w=48
\n" ); document.write( "6w/6=48/6\r
\n" ); document.write( "\n" ); document.write( "w=8 the width.
\n" ); document.write( "..
\n" ); document.write( "length = 2w-3
\n" ); document.write( "length = 2*8-3
\n" ); document.write( "16-3
\n" ); document.write( "=13
\n" ); document.write( "..
\n" ); document.write( "length =13feet, width =8feet
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
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