document.write( "Question 384638: the perimeter of a rectangle is 42 ft. The length of the rectangle is 3 ft less than twice the width.Find the length and the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #272287 by mananth(16946)![]() ![]() You can put this solution on YOUR website! width = w \n" ); document.write( "length = 2w-3\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "2*(l+w)=perimeter \n" ); document.write( "2*(w+2w-3)=42 \n" ); document.write( "2*(3w-3)=42 \n" ); document.write( "6w-6=42 \n" ); document.write( "+6 +6 \n" ); document.write( "6w=42+6 \n" ); document.write( "6w=48 \n" ); document.write( "6w/6=48/6\r \n" ); document.write( "\n" ); document.write( "w=8 the width. \n" ); document.write( ".. \n" ); document.write( "length = 2w-3 \n" ); document.write( "length = 2*8-3 \n" ); document.write( "16-3 \n" ); document.write( "=13 \n" ); document.write( ".. \n" ); document.write( "length =13feet, width =8feet \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |