document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384605>Question 384605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a nightmare with this one. Can someone please help me.\r<BR>\n" );
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document.write( "A 75-ft diagonal brace on a bridge connects a support of the center of the bridge to a side support on the bridge. The horizontal distance that it spans is 15 ft longer that the height that it reaches on the side of the bridge. Find the horizontal and vertical distances spanned by this brace.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272259 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You could use the Pythagorean theorem <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > to solve this problem.<BR>\n" );
document.write( "You have a right triangle whose hypotenuse is the 75ft. diagonal and whose height is h.  The base of this triangle is h+15ft.<BR>\n" );
document.write( "You need to find h and h+15.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=75%5E2+=+h%5E2%2B%28h%2B15%29%5E2 ALIGN=MIDDLE  ALT=\"75%5E2+=+h%5E2%2B%28h%2B15%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5625+=+h%5E2%2B%28h%5E2%2B30h%2B225%29 ALIGN=MIDDLE  ALT=\"5625+=+h%5E2%2B%28h%5E2%2B30h%2B225%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Rewrite as a quadratic equation in standard form.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2h%5E2%2B30h-5400+=+0 ALIGN=MIDDLE  ALT=\"2h%5E2%2B30h-5400+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide by 2 to simplify a bit.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%5E2%2B15h-2700+=+0 ALIGN=MIDDLE  ALT=\"h%5E2%2B15h-2700+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve by factoring.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28h%2B60%29%28h-45%29+=+0 ALIGN=MIDDLE  ALT=\"%28h%2B60%29%28h-45%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Apply the zero product rule.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2B60+=+0 ALIGN=MIDDLE  ALT=\"h%2B60+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h-45+=+0 ALIGN=MIDDLE  ALT=\"h-45+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+-60 ALIGN=MIDDLE  ALT=\"h+=+-60\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+45 ALIGN=MIDDLE  ALT=\"h+=+45\"   DISABLED_style= \"max-width:90%; height:auto;\" > Discard the negative solution as the height, h, is a positive quantity.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+45 ALIGN=MIDDLE  ALT=\"h+=+45\"   DISABLED_style= \"max-width:90%; height:auto;\" >feet. This is the vertical distance.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2B15+=+60 ALIGN=MIDDLE  ALT=\"h%2B15+=+60\"   DISABLED_style= \"max-width:90%; height:auto;\" >feet. This is the horizontal distance.<BR>\n" );
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document.write( "I do hope this takes care of your nightmare!<BR>\n" );
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