document.write( "Question 384489: A bus company has 4000 passengers daily, each paying a fee of 2$. For each 0.15$ increase, the company estimates that it will lose 40 passengers. If the company needs to take in $10 450 per day to stay in business, what fare should be charged? \n" ); document.write( "
Algebra.Com's Answer #272255 by ankor@dixie-net.com(22740)\"\" \"About 
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A bus company has 4000 passengers daily, each paying a fee of 2$.
\n" ); document.write( " For each 0.15$ increase, the company estimates that it will lose 40 passengers.
\n" ); document.write( " If the company needs to take in $10 450 per day to stay in business, what fare should be charged?
\n" ); document.write( ":
\n" ); document.write( "Use the given information write a revenue equation
\n" ); document.write( "Let x = no. of .15 increases above the 2.00 fare,
\n" ); document.write( "and x = no. of 40 passenger decreases from 4000
\n" ); document.write( "let y = daily revenue
\n" ); document.write( ":
\n" ); document.write( "The equation:
\n" ); document.write( "Revenue = fare * no. of passengers
\n" ); document.write( "y = (2 + .15x) * (4000 - 40x)
\n" ); document.write( "FOIL
\n" ); document.write( "8000 - 80x + 600x - 6x^2 = y
\n" ); document.write( ":
\n" ); document.write( "-6x^2 + 520x + 8000 = y
\n" ); document.write( ":
\n" ); document.write( "\"What fare increase will produce $10450 in daily revenue?+
\n" ); document.write( "y = 10450, find x
\n" ); document.write( "-6x^2 + 520x + 8000 = 10450
\n" ); document.write( ":
\n" ); document.write( "-6x^2 + 520x + 8000 - 10450 = 0
\n" ); document.write( ":
\n" ); document.write( "-6x^2 + 520x - 2450 = 0
\n" ); document.write( "Simplify, divide by -2
\n" ); document.write( "3x^2 - 260x + 1225 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(3x - 245) (x - 5) = 0
\n" ); document.write( "The reasonable solution
\n" ); document.write( "x = 5 ea .15 raises in fare will produce $10,450 revenue
\n" ); document.write( "Fare = 2.00 + 5(.15)
\n" ); document.write( "Fare = $2.75, is the required fare
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this using x = 5
\n" ); document.write( "5 ea 40 passenger decreases, from 4000 equal 3800 passengers
\n" ); document.write( "Rev = 2.75 * 3800
\n" ); document.write( "Rev = $10,450 \n" ); document.write( "
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