document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384601>Question 384601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is two less than twice its width.If the perimeter of the rectangle is 44 sq. units what are the dimensions of the rectangle?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272246 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width = w<BR>\n" );
document.write( "length = 2w-2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "perimeter = 44<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2*(l+w)=perimeter<BR>\n" );
document.write( "2*(w+2w-2)=44<BR>\n" );
document.write( "2*(3w-2)=44<BR>\n" );
document.write( "6w-4=44<BR>\n" );
document.write( "+4      +4<BR>\n" );
document.write( "6w=48<BR>\n" );
document.write( "/6<BR>\n" );
document.write( "w=8 units.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Length = 2w-2<BR>\n" );
document.write( "2*8-2<BR>\n" );
document.write( "=14 units<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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