document.write( "Question 384535: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution to get a 30% solution? \n" ); document.write( "

Algebra.Com's Answer #272205 by mtmorro(23) $\"\"$ $\"About$

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10% alcohol to be mixed with a 50 liters of 80% solution to get a 30% solution\r
\n" ); document.write( "\n" ); document.write( "Looks like 125 liters of 10% to make an 80% solution a 30% solution \r
\n" ); document.write( "\n" ); document.write( "start with 50 liter of 80% \r
\n" ); document.write( "\n" ); document.write( "when 150 liters of 10% this is how it works lets go in deluting step by step.\r
\n" ); document.write( "\n" ); document.write( "50 liter of 10% added to 50 liter of 80% divide in have 40% then add you 10% so with 100 liter you are at 50% with 50 liters added so it is now 100 liters\r
\n" ); document.write( "\n" ); document.write( "so now do the same thing add 100 liters to the current 100 then it divides by half to 20% now add the 10% you get 30% from the starting 50 liters of 80% solution. \r
\n" ); document.write( "\n" ); document.write( "What needs to be 50 liter than another 100 liter of 10% for a total of 150 liters added \r
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\n" ); document.write( "\n" ); document.write( "so adding 150 liters of 10% to 50 liter of 80% = 30% but at this time there will be 200 liters anwser 150 liters of 10% solution \r
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