document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384471>Question 384471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am really confused with this problem and I'm not sure how to find out the answer...\r<BR>\n" );
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document.write( "The length of the hypotenuse of a 30-60-90 triangle is 10. Find the length of the two legs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272178 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of the hypotenuse of a 30-60-90 triangle is 10. Find the length of the two legs.<BR>\n" );
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document.write( "The side opposite the 30 degree angle is half of the hypotenuse, or 5<BR>\n" );
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document.write( "Use Pythagoras to find the 3rd side:<BR>\n" );
document.write( "10^2 = 5^2 + x^2<BR>\n" );
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document.write( "x^2 = 100-25<BR>\n" );
document.write( "x^2 = 75<BR>\n" );
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document.write( "x =  5*sqrt(3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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