document.write( "Question 384475: 3ysquared + 2y=1 \n" ); document.write( "

Algebra.Com's Answer #272174 by stanbon(75887) $\"\"$ $\"About$

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3ysquared + 2y=1
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\n" ); document.write( "3y^2 + 2y -1 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "3y^2 + 3y-y -1 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "3y(y+1)-(y+1) = 0
\n" ); document.write( "(y+1)(3y-1) = 0
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\n" ); document.write( "y = -1 or y = 1/3
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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