document.write( "Question 384446: Please help me solve this equation. Primeter of a right triangle is 12 feet and one of it's legs measurae 3 feet . How do you find the lengh of the other leg and the hypotenuse \n" ); document.write( "

Algebra.Com's Answer #272163 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Perimeter of a right triangle is 12 feet. (thus the sum other two sides = 9ft)       
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document.write( "Let 3, x  and (9ft-x) represent the lengths of the sides
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document.write( "Applying the Pythagoream Theorem to solve for x
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document.write( " 3^2 + x^2 = (9ft-x)^2
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document.write( "Solving for x
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document.write( "  9 + x^2 = 81 - 18x + x^2
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document.write( "      18x = 72
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document.write( "        x = 4ft, length of the other leg and the hypotenuse is 5ft  (9ft-4ft)
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document.write( "CHECKING our Answer
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document.write( " 3^2 + 4^2 = 9 + 16 = 25 = 5^2 \n" );
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