document.write( "Question 384309: 5y+4y=19
\n" ); document.write( "y=6x-3\r
\n" ); document.write( "\n" ); document.write( "solve by the substitution method and by showing the steps.
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Algebra.Com's Answer #272118 by mananth(16946)\"\" \"About 
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5y+4y=19
\n" ); document.write( "y=6x-3\r
\n" ); document.write( "\n" ); document.write( "9y=19
\n" ); document.write( "substitute y in 9y=19
\n" ); document.write( "9(6x-3)=19
\n" ); document.write( "54x-27=19
\n" ); document.write( "+27
\n" ); document.write( "54x=46
\n" ); document.write( "x=46/54
\n" ); document.write( "x=23/27
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
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\n" ); document.write( "y=(6*23/27)-3
\n" ); document.write( "y=138/27 -3
\n" ); document.write( "y=(138-81)/27
\n" ); document.write( "y=57/27
\n" ); document.write( "y=19/9
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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