document.write( "Question 384309: 5y+4y=19
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document.write( "y=6x-3\r
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document.write( "solve by the substitution method and by showing the steps. \n" );
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Algebra.Com's Answer #272118 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 5y+4y=19 \n" ); document.write( "y=6x-3\r \n" ); document.write( "\n" ); document.write( "9y=19 \n" ); document.write( "substitute y in 9y=19 \n" ); document.write( "9(6x-3)=19 \n" ); document.write( "54x-27=19 \n" ); document.write( "+27 \n" ); document.write( "54x=46 \n" ); document.write( "x=46/54 \n" ); document.write( "x=23/27 \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( ".. \n" ); document.write( "y=(6*23/27)-3 \n" ); document.write( "y=138/27 -3 \n" ); document.write( "y=(138-81)/27 \n" ); document.write( "y=57/27 \n" ); document.write( "y=19/9 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |