document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384373>Question 384373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The age of Tim is 1 year more than twice of Carla's age. Three years ago, he was thrice as old as she was then. Find their present ages.\r<BR>\n" );
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document.write( "The sum of Gelard's age and Fred's is 53 an one-half ( 1/2 ) as old as Fred. Then How old is Fred? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272102 by </B><A HREF=/tutors/aboutme.mpl?userid=thinktank.experts><B>thinktank.experts(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thinktank.experts><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=thinktank.experts><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let carla age =x yrs.<BR>\n" );
document.write( "tim=2x+1\r<BR>\n" );
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document.write( "acc to the problem---\r<BR>\n" );
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document.write( "2x+1-3=3(x-3)<BR>\n" );
document.write( "2x-2=3x-9<BR>\n" );
document.write( "-x=-7<BR>\n" );
document.write( "so, x=7<BR>\n" );
document.write( "carla age=7yrs<BR>\n" );
document.write( "tim age=2*7+1=15yrs..<BR>\n" );
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