document.write( "Question 5363: I believe this is a mixture problem, but I am stuck at setting it up (formula). Can you please help me! Here is the question: How many ounces of pure water must be added to 60 oz of a solution that is 20% water to make a solution that is 30% water? I know this is not set up right.\r
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document.write( " Amount . rate = Quantity
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document.write( "Pure H20 x .30 .20x\r
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document.write( "60 oz. .20 \n" );
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Algebra.Com's Answer #2721 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = amount of pure water at 100% water\r \n" ); document.write( "\n" ); document.write( "60 = solution being mixed at 20% water\r \n" ); document.write( "\n" ); document.write( "x+60 = resulting mixture at 30% water.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From this, the equation is: \n" ); document.write( "1.00(x) + (.20)(60) = (.30)(x+ 60) \n" ); document.write( "1.00x + 1.20 = .30x + 1.80\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Appropriate simplification gives you \n" ); document.write( ".70x = .60 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It usually comes out more even than this, but sometimes life is like that. I think it's right. Anybody see an error?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |