document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384375>Question 384375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you write john is 11 more than twice as old as bob the sum of their ages is 65. find the ages of each. as a equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272098 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bob = x<BR>\n" );
document.write( "John = 2x+11<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+2x+11=65<BR>\n" );
document.write( "3x+11=65<BR>\n" );
document.write( "-11    -11<BR>\n" );
document.write( "3x=54<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x=18 Bob's age<BR>\n" );
document.write( "John = 2x +11= 2*18+11=47<BR>\n" );
document.write( "...<BR>\n" );
document.write( "47+18=65<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );