document.write( "Question 384366: don williams uses his small motorboat to go 3 miles up stream to his favorite fishing spot. against the current, the trip takes 3/5 hours. with the current the trip takes 1/5 hours. how fast is the boat on still water? what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #272094 by mananth(16946)\"\" \"About 
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boat speed x mph
\n" ); document.write( "current speed = y
\n" ); document.write( "...
\n" ); document.write( "upstream speed = x-y
\n" ); document.write( "downstream speed x+y
\n" ); document.write( "..
\n" ); document.write( "distance = 3 miles
\n" ); document.write( "..
\n" ); document.write( "t=d/r
\n" ); document.write( "..
\n" ); document.write( "3/(x-y)=3/5
\n" ); document.write( "cross multiply
\n" ); document.write( "3(x-y)15
\n" ); document.write( "/3
\n" ); document.write( "x-y =5.........................1
\n" ); document.write( "..
\n" ); document.write( "3/(x+y)=1/5
\n" ); document.write( "x+y =15.........................2
\n" ); document.write( "..
\n" ); document.write( "add 1 & 2
\n" ); document.write( "2x=20
\n" ); document.write( "/2
\n" ); document.write( "x= 10.\r
\n" ); document.write( "\n" ); document.write( "speed of boat in still water = 10 mph.
\n" ); document.write( "m.ananth@hotmail.ca
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