document.write( "Question 384366: don williams uses his small motorboat to go 3 miles up stream to his favorite fishing spot. against the current, the trip takes 3/5 hours. with the current the trip takes 1/5 hours. how fast is the boat on still water? what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #272094 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed x mph \n" ); document.write( "current speed = y \n" ); document.write( "... \n" ); document.write( "upstream speed = x-y \n" ); document.write( "downstream speed x+y \n" ); document.write( ".. \n" ); document.write( "distance = 3 miles \n" ); document.write( ".. \n" ); document.write( "t=d/r \n" ); document.write( ".. \n" ); document.write( "3/(x-y)=3/5 \n" ); document.write( "cross multiply \n" ); document.write( "3(x-y)15 \n" ); document.write( "/3 \n" ); document.write( "x-y =5.........................1 \n" ); document.write( ".. \n" ); document.write( "3/(x+y)=1/5 \n" ); document.write( "x+y =15.........................2 \n" ); document.write( ".. \n" ); document.write( "add 1 & 2 \n" ); document.write( "2x=20 \n" ); document.write( "/2 \n" ); document.write( "x= 10.\r \n" ); document.write( "\n" ); document.write( "speed of boat in still water = 10 mph. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |