document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384308>Question 384308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A yard has an area of 54 square inches and a perimeter of 42 inches. Find the length and width of the yard. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #272084 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=272084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have\r<BR>\n" );
document.write( "\n" );
document.write( "xy = 54, and\r<BR>\n" );
document.write( "\n" );
document.write( "2(x + y) = 42 --> x + y = 21\r<BR>\n" );
document.write( "\n" );
document.write( "This is a fairly easy case, as guess and check shows the dimensions to be 18 in. and 3 in. However if the values didn't reveal an obvious answer, you could solve it by defining a quadratic polynomial using Vieta's formulas (relating to the sum and product of roots). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );