document.write( "Question 384326: Solve e^2x -6e^x +5=0 algebraically. Find exact solutions, expressing the answer in terms of natural logarithms. \n" ); document.write( "
Algebra.Com's Answer #272064 by robertb(5830)\"\" \"About 
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The equation can be treated as a quadratic equation in \"e%5Ex\". That said, the equation factors as follows:
\n" ); document.write( "\"%28e%5Ex+-+1%29%28e%5Ex+-+5%29+=+0\".
\n" ); document.write( "Hence either \"e%5Ex+=+1\" or \"e%5Ex+=+5\".
\n" ); document.write( "These give the values x = 0 or x = ln5.
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