document.write( "Question 384248: The surface area of a rectangular box with a
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document.write( "square base is 54 square inches, and is given
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document.write( "A = 2x2 + 4xh
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document.write( "Find x when h = 3 inches.
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Algebra.Com's Answer #272041 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The surface area of a rectangular box with a square base is 54 square inches, \n" ); document.write( " and is given by: \n" ); document.write( "A = 2x^2 + 4xh \n" ); document.write( "2x^2 + 4xh = 54 \n" ); document.write( ": \n" ); document.write( "Find x when h = 3 inches. \n" ); document.write( "2x^2 + 4x(3) = 54 \n" ); document.write( "2x^2 + 12x - 54 = 0 \n" ); document.write( "Simplify divide by 2 \n" ); document.write( "x^2 + 6x - 27 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x+9)(x-3) = 0 \n" ); document.write( "Positive solution \n" ); document.write( "x = 3 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, find the surface area with x=3,h=3 \n" ); document.write( "A = 2(3^2) + 4*3*(3) \n" ); document.write( "A = 2(9) + 36 \n" ); document.write( "A = 18 + 36 \n" ); document.write( "A = 54 \n" ); document.write( " \n" ); document.write( " |