document.write( "Question 384282: A rectangle that the length is twice the with with an area of 50yd^2 \n" ); document.write( "
Algebra.Com's Answer #272039 by mananth(16949) You can put this solution on YOUR website! width = x \n" ); document.write( "length = 2x \n" ); document.write( ".. \n" ); document.write( "L*W=Area \n" ); document.write( "2x*x=50 \n" ); document.write( "2x^2=50 \n" ); document.write( "/2 \n" ); document.write( "x^2=25 \n" ); document.write( " \n" ); document.write( "x= 5 yard the width \n" ); document.write( ".. \n" ); document.write( "length = 2x = 10 yard the length \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |