document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=384176>Question 384176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by factoring and using the principle of zero products:<BR>\n" );
document.write( "2x^2-11x+15=0 OK I done this before but with the quadratic and square rooting I'm lost I done this much so far Please help I'm so lost with this \r<BR>\n" );
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document.write( "2(x-2)(x+2)-11+15 then add 11 on both sides which would be 2x2=4 and 15+11 =4 -11+11=0\r<BR>\n" );
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document.write( "this is my third sending!! hopefully i get some help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #271945 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=271945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have to FOIL two binomial factors to get 2x^2-11x+15\r<BR>\n" );
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document.write( "so the x terms of the binomials multiply to 2x^2 ___ like 2x and x\r<BR>\n" );
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document.write( "the constant terms multiply to 15 ___ 3 & 5 , and 1 & 15 are the choices\r<BR>\n" );
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document.write( "look at the center (x) term coefficient ___ it is negative<BR>\n" );
document.write( "this means that the factors of 15 must be negative ___ -3 & -5 , and -1 & -15\r<BR>\n" );
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document.write( "now the \"tricky\" part ___ the factors of the squared term (2x^2)<BR>\n" );
document.write( "are multiplied with the factors of the constant term (15)<BR>\n" );
document.write( "to end up with the coefficient of the x term (-11)<BR>\n" );
document.write( "you have to mix & match to get the right combination\r<BR>\n" );
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document.write( "2x * -3 = -6x<BR>\n" );
document.write( "x * -5 = -5x<BR>\n" );
document.write( "-5x + -6x = -11x\r<BR>\n" );
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document.write( "so the factors are ___ (2x - 5)(x - 3) = 0\r<BR>\n" );
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document.write( "2x - 5 = 0 ___ 2x = 5 ___ x = 5/2\r<BR>\n" );
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document.write( "x - 3 = 0 ___ x = 3 </SPAN>\n" );
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