document.write( "Question 42055: Express 1994 as a sum of coonsecutive positive integers and show this is the only way to do it. \n" ); document.write( "
Algebra.Com's Answer #27190 by kev82(151) ![]() You can put this solution on YOUR website! Hi,\r \n" ); document.write( "\n" ); document.write( "1994 can be written as 497+498+499+500 so there is how it's done. Proving this is the only way is quite simple but it's quite long and I don't really want to type it here. An outline of the proof is as follows.\r \n" ); document.write( "\n" ); document.write( "1) To write a number N as the sum of (possibly negative) consecutive integers, where the first term is a. Then\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) We can rearrage to find a\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3) We want a to be an integer so (replace equals with congruent to)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4) (Be careful with 2N congruent 0 mod 2n here!) If n is odd then this has a solution when n divides N. If n is even then there is solution when n does not divide N, but does divide 2N.\r \n" ); document.write( "\n" ); document.write( "5) So taking N=1994, the only values of n that satisfy the above conditions are n=4,997,3988. (N=1 is obviously a trivial solution, but you really want n>1 right?)\r \n" ); document.write( "\n" ); document.write( "6) Calculating a for the above 3 values gives 497, -496, and -1993. You are only interested in the sums which use strictly posotive numbers. There is only one of those, with n=4 which I gave you above.\r \n" ); document.write( "\n" ); document.write( "Hope that helps, \n" ); document.write( "Kev \n" ); document.write( " |