document.write( "Question 42036: Find two positive real numbers that differ by 1 and have a product of 1. \n" ); document.write( "
Algebra.Com's Answer #27187 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
Let 2 numbers be x and y\r
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\n" ); document.write( "\n" ); document.write( "We are told:
\n" ); document.write( "x-y=1\r
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\n" ); document.write( "\n" ); document.write( "and
\n" ); document.write( "xy=1\r
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\n" ); document.write( "\n" ); document.write( "Right then:
\n" ); document.write( "xy=1
\n" ); document.write( "means that x=1/y\r
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\n" ); document.write( "\n" ); document.write( "so we then get from x-y=1 that
\n" ); document.write( "(1/y)-y=1
\n" ); document.write( "--> \"+1-y%5E2+=+y+\"
\n" ); document.write( "\"+1+-+y%5E2+-+y+=+0+\"\r
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\n" ); document.write( "\n" ); document.write( "and re-arranging, gives \"+y%5E2+%2B+y+-+1+=+0+\"\r
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\n" ); document.write( "\n" ); document.write( "Not easy to factorise, so use the quadratic formula:
\n" ); document.write( "\"+y+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F%282a%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+y+=+%28-%281%29+%2B-+sqrt%28%281%29%5E2+-+4%281%29%28-1%29%29%29%2F%282%281%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+y+=+%28-1+%2B-+sqrt%281%2B4%29%29%2F%282%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+y+=+%28-1+%2B-+sqrt%285%29%29%2F%282%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Remember, we want positive answers, so of the 2 answers quoted above, only \"+y+=+%28-1+%2B+sqrt%285%29%29%2F%282%29+\" is acceptable.\r
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\n" ); document.write( "\n" ); document.write( "Now, if x-y=1 then x = 1+y. So,\r
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\n" ); document.write( "\n" ); document.write( "\"+x+=+%28-1+%2B+sqrt%285%29%29%2F%282%29+%2B+1+\"
\n" ); document.write( "\"+x+=+%28-1+%2B+sqrt%285%29%29%2F%282%29+%2B+2%2F2+\"
\n" ); document.write( "\"+x+=+%28-1+%2B+2+%2B+sqrt%285%29%29%2F%282%29+\"
\n" ); document.write( "\"+x+=+%281+%2B+sqrt%285%29%29%2F%282%29+\"\r
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\n" ); document.write( "\n" ); document.write( "jon.
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