document.write( "Question 42036: Find two positive real numbers that differ by 1 and have a product of 1. \n" ); document.write( "
Algebra.Com's Answer #27187 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! Let 2 numbers be x and y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We are told: \n" ); document.write( "x-y=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and \n" ); document.write( "xy=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Right then: \n" ); document.write( "xy=1 \n" ); document.write( "means that x=1/y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so we then get from x-y=1 that \n" ); document.write( "(1/y)-y=1 \n" ); document.write( "--> \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and re-arranging, gives \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Not easy to factorise, so use the quadratic formula: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remember, we want positive answers, so of the 2 answers quoted above, only \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, if x-y=1 then x = 1+y. So,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |